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4k^2-144k+1152=0
a = 4; b = -144; c = +1152;
Δ = b2-4ac
Δ = -1442-4·4·1152
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-144)-48}{2*4}=\frac{96}{8} =12 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-144)+48}{2*4}=\frac{192}{8} =24 $
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